Lcm And Hcf Questions Answers Pdf Model Questions & Answers, Practice Test for ibps rrb so officer sclae 2 3 single exam 2024

Answer: (d)

We are given that HCF = $p^2$ and the product of two non-zero expressions = $(x + y + z)p^3$

We know that HCF × LCM = Product of two numbers

Therefore,

$p^2 × LCM = (x + y + z)p^3$⇒LCM

= ${(x + y + z)p^3}/{p^2}$ = (x + y + z) p

Answer: (d)

27 × 1.$\ov2$ × 5.526$\ov2$ × 0.$\ov6$ = 27 × 1 $2/9 × 5{4736}/{9000} × 6/9$

= 27 × ${11}/9 × {49736}/{9000} × 6/9$

= ${11 × 49736 × 2}/{9000} = {1094192}/{9000}$ = 121.577

Answer: (d)

LCM of 42, 72 and 84 = 504

Difference between divisor and remainder

= 25 – 42 = 55 – 72 = 67 – 84

= – 17

Required number = 504 – 17 = 487.

Answer: (c)

Let $f_1(x) = (x^4 – y^4 ) = [(x^2)^2 – (y^2)^2]$

= $(x^2 – y^2 ) (x^2 + y^2)$

= (x – y) (x + y) ($x^2 + y^2$)

and $f_2(x) = (x^6 – y^6 ) = (x^3)^2 – (y^3)^2$

= ($x^3 + y^3) (x^3 – y^3$)

= (x + y) ($x^2 – xy + y^2) (x – y) (x^2 + xy + y^2$)

= (x – y) (x + y) ($x^2 – xy + y^2 ) (x^2 + xy + y^2$)

∴ HCF of $[f_1 (x), f_2 (x)] = (x – y) (x + y) = x^2 – y^2$

Answer: (d)

All the statement are true example for each statement.

1. take number 2 and 3

2. take number 7 and 25

3. take number 25 and 16 and many more.